9x^2-x+8=9-x

Solution for 9x^2-x+8=9-x equation:

9x^2-x+8=9-x

We move all terms to the left:

9x^2-x+8-(9-x)=0

We add all the numbers together, and all the variables

9x^2-x-(-1x+9)+8=0

We add all the numbers together, and all the variables

9x^2-1x-(-1x+9)+8=0

We get rid of parentheses

9x^2-1x+1x-9+8=0

We add all the numbers together, and all the variables

9x^2-1=0

a = 9; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·9·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*9}=\frac{-6}{18}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*9}=\frac{6}{18}
=1/3
$